Tuesday 23 December 2014

GENERAL KNOWLEDGE SOVED MODEL PAPER

GENERAL KNOWLEDGE SOVED MODEL PAPER

1. What is an antipyretic.
A substance used to lower body temperature.

2. What are asteroids.
Asteroids are small pieces of planet like material revolving around sun mostly found between orbits of mars and Jupiter.

3. What are lichens.
Lichens are a symbiotic association between algae and fungi often growing on rocks and tree trunks.

Sunday 14 December 2014

SOLVED MODEL QUESTION AND ANSWERS FOR UGC NET COMPUTER SCIENCE

SOLVED MODEL QUESTION AND ANSWERS FOR UGC NET COMPUTER SCIENCE

1. What is a disjoint set.
If two sets ‘A’ and ‘B’ have no elements in common then it is called as disjoint sets.

2. What is pushdown automata.
It is a finite automaton that makes use of stack.

3. What is the difference between Deterministic finite automata and Non deterministic finite automata.
Deterministic finite automata has unique next states.
Non deterministic finite automata has multiple next states.

Tuesday 25 November 2014

UGC NET GENERAL KOWLEDGE SOLVED PAPER 1

UGC NET GENERAL KOWLEDGE SOLVED PAPER 1

1. Mahalnobis model gave importance to.
Heavy Industries

2. Tank irrigation is popular in which region.
Deccan region

3. 5th five year plan was prepared by
DD Dhar

4. Who introduced zamindari system.
Cornwallis

MODEL SOLVED PAPER FOR UGC NET COMPUTER SCIENCE

MODEL SOLVED PAPER FOR UGC NET COMPUTER SCIENCE

1. Which method is used for resolving data dependency conflict by compiler.
Delayed load

2. Which gate  is used as anti coincidence detector.
Ex-OR

3. IPV4 is in which address format.
32 bit address format

4. In reverse polish notation, the expression A*B+C*D can be written as
AB*CD*+

Thursday 13 November 2014

SOLVED MODEL PAPER FOR UGC NET COMPUTER SCIENCE DECEMBER 2014

SOLVED MODEL PAPER FOR UGC NET COMPUTER SCIENCE DECEMBER 2014

1. What is meant by concurrency control mechanism.
Concurrency helps to prevent updation of the same record by two users at the same time.
For example, If a user is accessing a record, another user cannot access it till the first user completes updation. So a lock is enabled till a user completes the task. This is called as concurrency.

2. What are the levels of capability maturity model(CMM).
Level 1 – Initial
Level 2 – Repeatable
Level 3 - Defined
Level 4 – Managed
Level 5 – Optimizing

3. What is ATL.
The Active Template Library(ATL) is a set of template based c++ classes to simplify the programming of Component Object Model(COM) objects.
COM helps to create a variety of COM objects,OLE automation servers, Activex controls.

Sunday 9 November 2014

UGC NET GENERAL KOWLEDGE SOLVED MODEL PAPER

                      UGC NET GENERAL KOWLEDGE SOLVED MODEL PAPER

1. Who was the first scholar to use the term ‘Indus Valley Civilization’.
John Marshall

2. When did dual government begin in Bengal.
1765

3. Who founded Atmiya Sabha in 1815.
Raja Ram Mohan Roy

4. Who prepared Nehru Report, 1928.
Motilal Nehru and Tej Bahadur Sapru

Sunday 2 November 2014

UGC NET COMPUTER SCIENCE MODEL SOLVED PAPER 3 FOR DECEMBER 2014

UGC NET COMPUTER SCIENCE MODELSOLVED PAPER 3 FOR DECEMBER 2014

1. In delta rule for error minimization,
Weights are adjusted with reference to difference between desired output and actual output.

2. Which is the highest level of abstraction in a database.
View level

3. What is cluster analysis.
Cluster analysis or clustering is the task of assigning a set of objects in to groups so that the objects in the same cluster are more similar to one another.

Saturday 11 October 2014

SOLVED MODEL PAPER FOR UGC NET PAPER 2

SOLVED MODEL PAPER FOR UGC NET PAPER 2

1. What is the functionality of recursive foreign key.
A recursive foreign key references its own relation.

2. 5th Normal form is concerned with
Join dependency

3. Which Normal form is considered adequate for normal database design.
3NF

4. Which two files is used during operation of DBMS.
Data dictionary and transaction log

Saturday 27 September 2014

GENERAL KNOWLEDGE SOLVED MODEL PAPER

GENERAL KNOWLEDGE SOLVED MODEL PAPER

1. Which of the following is a part of the English language which helps us to understand
sounds of various alphabets?
(A) Phonetics
(B) Homophones
(C)Both (a) and (b)
(D) None

Ans.: A.)

2. Research is done for
(A) Knowledge of research process
(B) Solving a  problem
(C) Interest in research
(D) Experience

Ans.: B.)

3. One of the essential characteristics of research is
(A) Sensitivity
(B) Generalizability
(C) Usability
(D) Replicability

Ans.: C.)

Saturday 20 September 2014

UGC NET MODEL SOLVED PAPER FOR DECEMBER 2014

UGC NET MODEL SOLVED PAPER FOR DECEMBER 2014

1. Every time attribute P appears, it is matched with the same value of attribute Q, but not the same
value of attribute R. Therefore, it is true that:
(A) P ®Q
(B) P ®R
(C) P ® (Q,R).
(D) (Q,R)® P
Ans.: A.
Reason: Value of P matches only with value of Q

2. A 3NF removes
A. Repeating groups
B. Partial functional dependency
C. Transisitive functional dependency
D. Other higher functional dependency
Ans.: C.
Reason: Transitive functional dependency exists when a non key attribute value is functionally dependent on another non key attribute

Saturday 13 September 2014

IMPORTANT SOLVED MODEL TEST PAPER FOR UGC NET DECEMBER 2014

IMPORTANT SOLVED MODEL TEST PAPER FOR UGC NET DECEMBER 2014

1. The total number of spanning trees that can be drawn using five labeled vertices is:
(A). 125 (B).64
(C ). 36 (D). 16

Ans : A.
Explanation:
As per Cayleys formula for counting spanning trees
T(Kn)= n^ (n-2) where n is the number of vertices.
T(k5)=5 5-2=5 3= 5 * 5 * 5=125

2. Four jobs J1,J2,J3, and J4 are waiting to be run. Their expected run times are 9,6,3 and 5 respectively. In order to minimize average response time, the jobs should be run in the order:
(A). J1 J2 J3 J4 (B). J4 J3 J2 J1
(C ) J3 J4 J1 J2 (D) J3 J4 J2 J1
Ans : D

Easy one
J3=3
J4=5
J2=6
J1=9

3. If a code is ‘t’ error detecting, the minimum hamming distance should be equal to :
(A). t-1 (B). t
(C ). t+1 (D). 2t+1

Ans: C.
Very often asked question.
Tip:
For error detection, formula is t+1
For error correction, formula is 2t+1

Monday 8 September 2014

RESEARCH APTITUDE SOLVED PAPER FOR UGC NET AND OTHER RESEARCH COMPETITIVE EXAMS

RESEARCH APTITUDE SOLVED PAPER FOR UGC NET AND OTHER RESEARCH ENTRANCE EXAMS

1. A good researcher lays his hands on
a. A specific area and tries to understand it in minute details
b. Several areas and tries to understand them at fundamental level
c. Any area ,as long as manpower and funding are available in plenty
d. All the above
Ans. (a)

2. Which research paradigm is based on the pragmatic view of reality?
a. quantitative research
b. qualitative research
c. mixed research
d. none of the above
Ans. (c)

3. Which scientific method focuses on testing hypotheses developed from theories?
a. Deductive method
b. Inductive method
c. Hypothesis method
d. Pattern method
Ans. (a)

Saturday 9 August 2014

UGC NET COMPUTER SCIENCE JUNE 2014 SOLVED PAPER 3


UGC NET COMPUTER SCIENCE JUNE 2014 SOLVED PAPER 3

1. Line caps are used for adjusting the shape of the line ends to give them a better appearance. Various kinds of line caps used are
Butt cap, sharp cap and round cap

2. Match the following
Primitives                -        Attributes
Line                            -         Type,width,color
Fill Area                  -          Style,color,pattern
Text                          -           Color,size,font
Marker                -              Type, size,color

3. Which of the color models are defined with three primary colors.
RGB and HSV color models

4. Perceptron learning, delta learning and LMS learning comes under
Error correction learning-learning with a teacher


Sunday 3 August 2014

UGC NET COMPUTER SCIENCE JUNE 2014 SOLVED PAPER 2

UGC NET COMPUTER SCIENCE JUNE 2014 SOLVED PAPER 2

1.      Infrared signals can be used for short range  communication  in  a  closed area using propagation.
(A)   ground            (B)    sky
(C)    line of sight    (D)    space

Ans.: C.) Line of Sight
Question from Mobile Computing
Very easy

2.    A  bridge  has  access  to address in the same network.
(A)   Physical    (B)    Network
(C)    Datalink    (D)   Application

Ans.: A.) Physical Layer
Data Communication and networks

3. The bit rate of a signal is 3000 bps. If each signal unit carries 6 bits, the baud rate of the signal is    .
(A)    500 baud/sec
(B)    1000 baud/sec
(C)    3000 baud/sec
(D)    18000 baud/sec

Ans.: A.) 500 baud/sec.
Very easy
Tip: Baud rate=Bit rate/N
So 3000/6=500




Friday 27 June 2014

COMPUTER SCIENCE SOLVED MODEL PAPER FOR UGC NET JUNE 2014


COMPUTER SCIENCE SOLVED MODEL PAPER FOR UGC NET JUNE 2014

1. What is Checksum/Hash sum
 A Checksum is a fixed size datum computed from an arbitrary block of digital data for the purpose of detecting accidental errors that may have been introduced during transmission or storage.

2. What are the five levels of Capability Maturity Model(CMM)
Initial
Repeatable
Defined
Managed
Optimizing

3. What is the use of ZAP command.
ZAP command removes all records from the table leaving just the table structure.
Records that are zapped cannot be retrieved.

Friday 13 June 2014

How to build Self Confidence: The key to success in Exams

Hi dudes.
As NET exam is about to be held in a few days, I thought of sharing some tips on gaining confidence to do your exams in a grand way.

Self Confidence is such a powerful tool that if you have mastery over it, you can scale greater heights in life easily. So I wish to list out a set of self confidence building techniques that you got to develop to climb the ladder of success quickly.  

* Believe Yourself.

Trust is the most basic and vital component that helps you to decide whether you will achieve what you aspire for.

For example. You have to attend an interview and inside your heart you think that I can  succeed in this interview with flying colours. If such is your intention, you will definitely succeed. But if you don't trust yourself, ultimately the result will be negative.
So learn to trust yourself and you will succeed irrespective of any difficult situation.



Monday 9 June 2014

COMPUTER SCIENCE STUDY MATERIAL FOR NET EXAM


1. The minimum number of page frames that must be allocated to a running process in a virtual memory environment is determined by.
Number of processes in memory

 2. The goal of structured programming is to.
 Be able to infer the flow of control from the program text.

3. Consider a basic block
a = b+c
c = a+d
d = b+c
e = d-b
a = e+b

Friday 30 May 2014

GENERAL KNOWLEDGE SOLVED QUESTION AND ANSWERS FOR ALL EXAMS

GENERAL KNOWLEDGE SOLVED QUESTION AND ANSWERS

1. Who was the constitutional advisor to constituent assembly.
B.N. Rao.

2. Constitution of India was adopted on
26th November 1949

3. The authority to alter boundaries of states in India lies with
The parliament

4. Sarkaria commission was related to
Centre-state relations

Friday 23 May 2014

MODEL SOLVED PAPER FOR UGC NET COMPUTER SCIENCE JUNE 2014

MODEL SOLVED PAPER FOR UGC NET JUNE 2014

1. A chip having 200 gates will be classified as
(A) SSI
(B) MSI
(C) LSI
(D) VLSI
Ans:-B

Note:
Small Scale Integration(SSI) - <10
Medium Scale Integration(MSI) - between 10 to 1000
Large Scale Integration(LSI) – Greater than 1000
Very Large Scale Integration(VLSI) – greater than 100000.

2. Consider the following statements :
I. Recursive languages are closed under complementation.
II. Recursively enumerable languages are closed under union.
III. Recursively enumerable languages are closed under complementation.
Which of the above statements are true ?

(A) I only
(B) I and II
(C) I and III
(D) II and III
Ans:-B



Sunday 11 May 2014

HOW TO READ BOOKS AND MAKES NOTES FOR UGC NET EXAM


HOW TO READ BOOKS AND MAKE NOTES FOR UGC NET EXAM
Many of the readers of my blog have asked question about how to read books. It is indeed a tedious job to read many gigantic books for an exam like UGC NET exam. But let me unlock the secrets of how to read books smartly and assure your success  in the exam.
The first and foremost problem with many aspirants is that they get frightened when they see big sized books and lose interest to prepare for the exam. This attitude needs  to be changed.



Sunday 4 May 2014

UGC NET COMPUTER SCIENCE SOLVED MODEL PAPER FOR JUNE 2014



UGC NET COMPUTER SCIENCE SOLVED MODEL PAPER FOR JUNE 2014

1. What is the difference between normalized data and denormalised data.
Normalised data means it has many tables and few columns per table.
Denormalised data means it has few tables, many columns per table.

2. Analysis of large database to retrieve information is called as
OLAP (On-Line Analytical Processing).

3. What is meant by deferred update.
It is the process in which all the log files entries are made first but the actual updates are done later.

4. What is a recursive foreign key.
It is a key which references its own relation.

Tuesday 22 April 2014

General Knowledge Solved Model Paper for UGC NET JUNE 2014

         GENERAL KNOWLEDGE SOLVED MODEL PAPER FOR UGC NET 2014 EXAM

1. Who is the first governor general of India.
Lord William Bentinck.

2. Young Bengal movement was started by.
Henry Louis Vivian Derozio.

3. The demand for 'swaraj'(self government)  was made by Indian National Congress(I.N.C.) for the first time.
At Calcutta session, 1906 under the chairmanship of Dadabhai Naoroji.

4.  The communal award was announced by
Ramsay Mcdonald 



Wednesday 16 April 2014

TIPS ON HOW TO PREPARE FOR PAPER 3 OF UGC NET COMPUTER SCIENCE

HOW TO PREPARE FOR CORE AND ELECTIVE PART OF UGC NET COMPUTER SCIENCE PAPER 3


If you look the syllabus of ugc net computer science particularly for paper 3, it’s a huge ocean. So mastering over all areas is simply not an easy task. So you got to focus upon some of the conventional areas where questions are often asked.
In paper 3 you all know that there are two parts, core part and elective part. Concentrate more on core part as it contains popular subjects and also easy to learn. There are actually 14 sections.


Tuesday 8 April 2014

SYNCHRONIZATION BASICS FOR UGC NET EXAM

SYNCHRONIZATION BASICS FOR UGC NET EXAM

Synchronization : The concept of Synchronization is concerned with cooperating
processes that share some resources. Co-operating processes must
synchronize with each other when they use shared resources. Thus we can view
the Synchronization as a set of constraints on the ordering of events.
Semaphores : A Semaphore is a protected variable whose value can be accessed
and altered only by operations P and V.
A Semaphore Mechanism basically consists of the two primitive operations
SIGNAL and WAIT.

Wednesday 26 March 2014

DIFFERENCE BETWEEN WHITE BOX TESTING AND BLACK BOX TESTING

       
Difference between white box testing and black box testing
White box testing:
          White box testing strategy deals with the internal logic and structure of the code. White box testing is also called as glass, structural, open box or clear box testing. The tests written based on the white box testing strategy incorporate coverage of the code written, branches, paths, statements and internal logic of the code etc.
In order to implement white box testing, the tester has to deal with the code and hence is needed to possess knowledge of coding and logic i.e. internal working of the code. White box test also needs the tester to look into the code and find out which unit/statement/chunk of the code is malfunctioning.

Wednesday 5 March 2014

UGC NET GENERAL PAPER 1 SOLVED MOCK TEST PAPER

UGC NET PAPER 1 SOLVED MOCK TEST PAPER

1. A teacher can develop social values among students by
(a) telling them about great people
(b) developing sense of discipline
(c) behaving ideally
(d) telling them good stories
Ans.: c

2. The ideal teacher
(a) Teaches the whole curriculum
(b) Helps his students in learning
(c) Is a friend, philosopher and guide
(d) Maintains good discipline
Ans.: c

3. The aim of education should be
(a) To develop vocational skills in the students
(b) To develop social awareness in the students
(c) To prepare the students for examination
(d) To prepare the students for practical life
Ans.: d


Monday 24 February 2014

UGC NET COMPUTER SCIENCE DECEMBER 2013 SOLVED PAPER 3

        
  UGC NET COMPUTER SCIENCE DECEMBER 2013 PAPER SOLVED PAPER 3


1. If the primal Linear Programming problem has unbounded solution, then it's dual problem will have
(A) feasible solution
(B) alternative solution
(C) no feasible solution at all
(D) no bounded solution at all
Ans.: c.)
Linear programming.

2. Match the following :
List -1                         List-II
a. Data coupling       i. Module A and Moduie B have shared data
b. Stamp coupling     ii. Dependency between modules is based on the fact they communicate by only passing of data
c. Common coupling   iii. When complete data structure is passed from one module to another
d. Content coupling   iV. When the control is passed from one module to the middle of another
Codes :    
    a       b    c        d
(A)   iii       ii    i       iv
(B)    ii       iii    i       iv
(C)    ii       iii    iv       i
(D)   iii      ii    iv       i
Ans.:  b.)
Software engineering

3.  A process which defines a series of tasks that have the following four primary objectives is known as
1. to identify all items that collectively define the software configuration.
2. to manage changes to one or more of these items.
3. to facilitate the construction of different versions of an application.
4. to ensure that software quality is maintained as the configuration evolves over time.
(A) Software Quality Management Process
(B) Software Configuration Management Process
(C) Software Version Management Process
(D) Software Change Management Process
Ans.: b.)
Software engineering

Monday 17 February 2014

Testimonial



Hi friends,
Today I am happy to convey you all that one of the readers of my blog http://www.netcomputerscience.in
has passed APSLET EXAM 2013.
This is what he said about his success:

"HAI, I AM  RAGHAVENDRARAO PAVULURI FROM ANDHRA PRADESH.

I MET YOU IN NETCOMPUTERSCIENCE.IN WEB SITE,I READ ALL THE
SUGGESTIONS THAT YOU GIVEN IN THAT.

I AM VERY THANKFUL TO YOU THOSE ARE ALL VALUEABLE TO ME.I HAVE JUST CLEAR APSLET EXAM 2013 .

NOW  I AM PREPARING FOR UGC NET".



Sunday 16 February 2014

UGC NET COMPUTER SCIENCE DECEMBER 2013 SOLVED PAPER 2 WITH EXPLANATION


UGC NET COMPUTER SCIENCE DECEMBER 2013 SOLVED PAPER 2 WITH EXPLANATION

1.  When data and acknowledgement are sent in the same frame, this is called as
(A) Piggy packing
(B) Piggy backing
(C) Back packing
(D) Good packing

Ans.: b.)
Piggybacking is a bi-directional data transmission technique in the network layer (OSI model).
Network question.

2. Encryption and Decryption is the responsibility of Layer.
(A) Physical
(B) Network
(C) Application
(D) Datalink

Ans.: c.)
Networking related.
Encryption is typically done at this level too, although it can be done on the application, session, transport, or network layers.

3. Using the RSA public key crypto system, if p = 13, q = 31 and d = 7, then the value of e is
(A) 101  (C) 105
(B) 103  (D) 107

Ans.: b.)
Network security and cryptography



Monday 27 January 2014

NEW STRATEGY ON HOW TO PASS UGC NET COMPUTER SCIENCE WITH REFERENCE BOOK LIST


STRATEGY TO CLEAR PAPER 2 & 3 OF UGC NET COMPUTER SCIENCE WITH REFERENCE BOOK DETAILS

Hi friends.
In this article I will explain you all about some of the new approaches that can be followed to clear the exam easily.

WRITING PRACTICE: Writing practice holds the key to success in NET exam particularly for paper 3. As you all are aware of the fact that this is an All India Exam, you have to learn and practice writing a lot prior to the exam. The more you practice, the better your chances to succeed in this exam.

SURFING ON THE INTERNET: Internet surfing is another vital factor because you cannot find everything prescribed in the syllabus in text books. It is also not possible to buy all the books. So you can search in the internet to get access to relevant information of various topics. Make internet surfing your hobby.

Tuesday 14 January 2014

MOCK TEST SOLVED PAPER FOR UGC NET COMPUTER SCIENCE AND CAMPUS INTERVIEWS


MOCK TEST FOR UGC NET COMPUTER SCIENCE AND OTHER CAMPUS INTERVIEWS

1.  A  2MB PCM(pulse code modulation) has
31 voice channels & 1 signalling channel.

2. What is Buffering.
Buffering is the process of temporarily storing the data to allow for small variation in device speeds.

3. What is a terminal emulation.
A software that allows a personal computer to pretend as a computer terminal is called as terminal emulation.